[Hackerrank] Finding the percentage

문제 설명

The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

제한사항

Input Format

The first line contains the integer n, the number of students’ records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.

Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Others

• 2 $\leq$ n $\leq$ 10
• 0 $\leq$ marks[i] $\leq$ 100
• length of marks arrays = 3

입출력 예

Sample Input 0

3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika

Sample Output 0

56.00

Idea

백준이랑 프로그래머스 같은 국내사이트들도 훌륭하지만,
영어공부의 필요성을 느껴서, hackerrank site의 문제들을 풀고있다.
순서대로 풀고있어서, 쉬운문제를 풀고있지만, 점점 어려워질것같다!
아래와 같이 풀어보았다..
코드잼도 풀어서 올려야겠다.

Code

if __name__ == '__main__':
    n = int(input())
    student_marks = {}
    for _ in range(n):
        name, *line = input().split()
        scores = list(map(float, line))
        student_marks[name] = scores
    query_name = input()
    
    select_score = list()
    for key, scores in student_marks.items():
        if key == query_name:
            select_score = scores
    
    
    print(f"{(sum(select_score) / len(select_score)):.2f}")

Explain

baseline code들을 최대한 안 건드리고 푸는식으로 계속 진행하고 있다.
설명 패스!!