[Hackerrank] Grading Students

문제 설명

HackerLand University has the following grading policy:

• Every student receives a grade in the inclusive range from 0 to 100.
• Any grade less than 40 is a failing grade.

Sam is a professor at the university and likes to round each student’s according to these rules:

• If the difference between the grade and the next multiple of 5 is less than 3, round grade up to the next multiple of 5.
• If the value of grade is less than 38, no rounding occurs as the result will still be a failing grade.

성적을 입력받고, 입력받은 성적을 5또는10을 뺏을때 3보다 작으면 반올림하고, 3보다 같거나 크면, 반올림 없다. 40점미만은 반올림 없다.

제한사항

Input Format

• The first line contains a single integer, n, the number of students.
• Each line i of the n subsequent lines contains a single integer, grades[i].

Output Format

• int[n]: the grades after rounding as appropriate

Others

• 1 ≤ n ≤ 60
• 0 ≤ grades[i] ≤ 100

입출력 예

Sample Input

haveaniceday

Sample Output

hae and via ecy

Idea

처음에 5의 배수를 어떻게 구해야 하나 고민했는데, 생각해보니깐 나머지 개념을 이용해도 바로 풀리는걸로

Code

def gradingStudents(grades):
    # Write your code here
    result = list()
    for data in grades:
        temp = math.ceil(data / 5)
        # print(temp)
        if data < 38:
            print(f"temp = {temp*5} input data = {data}")
            result.append(data)
        elif data % 5 not in [3,4]:
            print(f"temp = {temp*5} input data = {data}")
            result.append(data)
        else:
            #  temp - data >= 3:
            print(f"temp = {temp*5} input data = {data}")
            result.append((temp)*5)
    return result

Explain

파이썬스럽지는 않지만 문제를 푼거에 만족